Free for students · Ad-free · WCAG 2.1 AA Compliant · Accessibility

Newton's First Law

Lesson ~11 min read 8 MCQs

In simple terms: In simple terms, Newton's First Law says an object's motion won't change unless a net force acts on it. An object at rest stays at rest, and an object in motion stays in motion at the same speed and in the same direction.

Why this matters

Have you ever been on a long road trip, driving down a straight highway? You set the cruise control to 65 mph and for miles, the car just... goes. Your foot is off the gas pedal, but the car doesn't slow down, and it doesn't speed up. It just maintains that perfect 65 mph.

You might think, "The engine is pushing the car forward, so there must be a forward force." And you're right! But what about air resistance pushing back on the car? And friction in the tires? Those are forces, too.

The magic of cruise control is that the engine adjusts its push to be exactly equal and opposite to all the forces trying to slow you down. All the forces cancel out. This state of balanced forces is the key to Newton's First Law, and it explains why things can be moving without speeding up or slowing down. We'll explore both sides of this law: objects staying still and objects moving steadily.

Diagram

Newton's First Law: Translational Equilibrium A diagram showing two scenarios of translational equilibrium. On the left, a book at rest on a table has balanced vertical forces (Normal and Weight). On the right, a crate moving at constant velocity has balanced vertical forces and balanced horizontal forces (Push and Friction). Newton's First Law: Translational Equilibrium ΣF⃗ = 0 Case 1: At Rest (v⃗ = 0) Book w⃗ N⃗ ΣFᵧ = N - w = 0 Object remains at rest. Case 2: Constant Velocity (v⃗ = const.) Crate v⃗ w⃗ N⃗ P⃗ f⃗ₖ ΣFᵧ = N - w = 0 ΣFₓ = P - fₖ = 0 Object moves at constant velocity.
This diagram illustrates Newton's First Law with two scenarios. The left side shows a book at rest on a table, with a free-body diagram indicating its upward normal force and downward weight are balanced. The right side shows a crate being pushed at a constant velocity, with a free-body diagram showing that both vertical forces (normal and weight) and horizontal forces (push and friction) are balanced.

Concept map

flowchart TD
    A[Start: Analyze forces on an object] --> B{Is the net force zero? (ΣF = 0)};
    B -- Yes --> C{Is the object's initial velocity zero?};
    B -- No --> D[Object accelerates (a ≠ 0) --- Newton's 2nd Law];
    C -- Yes --> E[Object remains at rest (Static Equilibrium)];
    C -- No --> F[Object continues at constant velocity (Dynamic Equilibrium)];
This diagram illustrates Newton's First Law with two scenarios. The left side shows a book at rest on a table, with a free-body diagram indicating its upward normal force and downward weight are balanced. The right side shows a crate being pushed at a constant velocity, with a free-body diagram showing that both vertical forces (normal and weight) and horizontal forces (push and friction) are balanced.

Core explanation

Let's break down one of the most fundamental ideas in all of physics. It might seem simple at first, but it has some subtleties that are really important to master for the AP exam.

What is "Net Force"?

Imagine a game of tug-of-war. Team A pulls to the left with 100 pounds of force. Team B pulls to the right with 100 pounds of force. What happens to the rope? Nothing. It stays put. The forces are balanced.

Now, what if Team B brings in their friend Marcus, and they now pull to the right with 120 pounds of force? The rope will start moving to the right. The forces are unbalanced.

The net force is the overall, total force on an object after you add up all the individual forces, considering their directions. It's the vector sum of all forces. We write this as:

ΣF⃗ = F⃗₁ + F⃗₂ + F⃗₃ + ...

The Greek letter Sigma (Σ) just means "sum of." So, ΣF⃗ means "the sum of all force vectors." In our first tug-of-war game, the net force was zero. In the second game, it was 20 pounds to the right.

Translational Equilibrium: The State of Balance

When the net force on an object is zero, we say the object is in translational equilibrium.

ΣF⃗ = 0

This is the mathematical condition for Newton's First Law. "Translational" just refers to motion where the object moves from one point to another without rotating. "Equilibrium" means balance. So, it's a balance of forces that affects straight-line motion.

Newton's First Law: The Law of Inertia

Here's the law itself:

An object at rest stays at rest, and an object in motion stays in motion with the same speed and in the same direction unless acted upon by a nonzero net force.

In simpler terms: If ΣF⃗ = 0, then the object's velocity v⃗ is constant.

This is where we need to be very careful. "Constant velocity" has two important meanings:

  1. The object is at rest (v⃗ = 0).
  2. The object is moving at a constant speed in a straight line (v⃗ = constant ≠ 0).

Case 1: Static Equilibrium (At Rest) This is the intuitive one. A book sitting on your desk. Gravity pulls it down. The desk pushes it up with an equal and opposite normal force. The net force is zero, so the book just sits there. Its velocity is constant (at zero).

Case 2: Dynamic Equilibrium (Constant Velocity) This is where most students get stuck. They think that if an object is moving, there must be a net force causing the motion. This is the biggest misconception in early physics.

A net force doesn't cause velocity. A net force causes a change in velocity (acceleration).

Think back to the car on cruise control. The engine provides a forward push (applied force). Air resistance and friction provide a backward drag (resistive forces). At 65 mph, these forces are perfectly balanced. ΣF⃗ = 0. Because the net force is zero, the velocity doesn't change. It stays at a constant 65 mph. If you wanted to speed up to 70 mph (i.e., accelerate), you'd need to hit the gas, making the engine's force greater than the drag, creating a nonzero net force.

Forces are Independent in Different Dimensions

Forces are vectors, which means they have direction. We can analyze the forces in the horizontal (x) and vertical (y) dimensions separately. An object can be in equilibrium in one dimension but not the other.

Imagine sliding a puck across a perfectly frictionless air hockey table.

  • Vertical (y-direction)
    The force of gravity pulls the puck down. The table pushes it up with a normal force. These are balanced. ΣF_y = 0. The puck isn't flying up into the air or crashing through the table.
  • Horizontal (x-direction)
    Once you push it, there are no horizontal forces (we said it's frictionless!). So, ΣF_x = 0.

Because the net force is zero in both dimensions, the puck will glide at a constant velocity forever (or until it hits a wall). Its vertical velocity stays zero, and its horizontal velocity stays constant.

What's an Inertial Reference Frame?

This is a slightly more advanced idea, but it's the foundation for all of Newton's laws. An inertial reference frame is a point of view (a coordinate system) that is not accelerating.

Imagine you're on a smoothly moving train. If you toss a ball in the air, it goes up and comes straight back down into your hand, just like it would if you were standing on the ground. The train (and the ground) are inertial reference frames. Newton's First Law works perfectly.

Now, imagine the train suddenly lurches forward. If you toss the ball up, it will seem to fly backward relative to you. From your perspective, it accelerated backward without any horizontal force acting on it! This violates Newton's First Law. That's because you are in a non-inertial (accelerating) reference frame.

For AP Physics 1, you can almost always assume you are working in an inertial reference frame, like a lab on Earth. The key takeaway is that Newton's laws only hold true from a non-accelerating viewpoint.

Worked examples

Let's apply these concepts to a couple of classic AP-style problems.

Example 1

A Hanging Traffic Light (Static Equilibrium)

Problem: A 12 kg traffic light is suspended by two cables as shown. Cable 1 makes a 30° angle with the horizontal, and Cable 2 makes a 45° angle. Find the tension in each cable. (Use g = 9.8 m/s²)

Solution Walkthrough:

  1. 1
    Identify the Goal
    We need to find the magnitudes of the tension forces, T₁ and T₂.
  2. 2
    Analyze the State
    The traffic light is "suspended," meaning it's at rest. It is in static equilibrium. This is our key insight! It tells us the net force is zero: ΣF⃗ = 0.
  3. 3
    Break it Down
    Since the net force is zero, the net force in the x-direction must be zero (ΣF_x = 0), and the net force in the y-direction must be zero (ΣF_y = 0).
  4. 4
    Draw a Free-Body Diagram (FBD)
    Draw a dot for the light. Draw three forces acting on it:
    • Weight (w⃗) pointing straight down.
    • Tension 1 (T⃗₁) pointing up and to the left at 30°.
    • Tension 2 (T⃗₂) pointing up and to the right at 45°.
  5. 5
    Set up Equations
    We need to resolve T₁ and T₂ into their x and y components.
    • T₁x = -T₁cos(30°) (negative because it points left)
    • T₁y = +T₁sin(30°)
    • T₂x = +T₂cos(45°)
    • T₂y = +T₂sin(45°)
    • The weight is w = mg = (12 kg)(9.8 m/s²) = 117.6 N. It's all in the y-direction.
  6. 6
    Apply Equilibrium Conditions
    • ΣF_x = 0
      T₂cos(45°) - T₁cos(30°) = 0 T₂cos(45°) = T₁cos(30°)
    • ΣF_y = 0
      T₁sin(30°) + T₂sin(45°) - w = 0 T₁sin(30°) + T₂sin(45°) = 117.6 N
  7. 7
    Solve the System of Equations
    This is now an algebra problem. From the x-equation, we can express T₂ in terms of T₁: T₂ = T₁ * (cos(30°)/cos(45°)) ≈ T₁ * (0.866 / 0.707) ≈ 1.225 * T₁

    Now, substitute this into the y-equation: T₁sin(30°) + (1.225 * T₁)sin(45°) = 117.6 T₁(0.5) + (1.225 * T₁)(0.707) = 117.6 0.5 * T₁ + 0.866 * T₁ = 117.6 1.366 * T₁ = 117.6 T₁ ≈ 86.1 N

    Finally, find T₂: T₂ ≈ 1.225 * (86.1 N) ≈ 105.5 N

Why this matters: This problem shows how to use the fact that ΣF=0 in both dimensions to solve for unknown forces. The most common mistake is forgetting to break the tension forces into components.

Example 2

Pushing a Crate (Dynamic Equilibrium)

Problem: Aaliyah pushes a 40 kg crate across a floor at a constant velocity of 1.5 m/s. She pushes with a force of 150 N. What is the force of kinetic friction (fₖ)?

Solution Walkthrough:

  1. 1
    Identify the Goal
    Find the force of kinetic friction, fₖ.
  2. 2
    Analyze the State
    The key phrase is "constant velocity." This immediately tells you the crate is in dynamic equilibrium. The net force is zero: ΣF⃗ = 0.
  3. 3
    Focus on the Relevant Dimension
    Friction is a horizontal force. Aaliyah's push is also horizontal. So let's analyze the x-direction.
  4. 4
    Apply Equilibrium
    Since the net force is zero overall, it must be zero in the horizontal direction: ΣF_x = 0.
  5. 5
    Set up the Equation
    The forces in the x-direction are the applied push (F_push) and the kinetic friction (fₖ), which opposes the motion. ΣF_x = F_push - fₖ = 0 F_push = fₖ
  6. 6
    Solve
    We are given that F_push = 150 N. Therefore, fₖ = 150 N.

Where students slip up: Many students see motion and think there must be a net force. They might try to use F=ma. But a is acceleration, the change in velocity. Since the velocity is constant, the acceleration is zero! So F_net = m * 0 = 0, which brings us right back to Newton's First Law.

Try it yourself

Ready to test your understanding? Sketch a free-body diagram for each problem first!

  1. 1
    The Bookshelf
    A 5.0 kg textbook is sitting on a level bookshelf. A student, Priya, pushes horizontally on the book with a force of 10 N, but the book doesn't move. What is the magnitude of the static friction force acting on the book?

    Hint: The key words are "doesn't move." What does this tell you about the book's state of equilibrium and the net force on it?

  2. 2
    The Skier
    A 60 kg skier is gliding down a slope at a constant speed. The slope is angled at 15° to the horizontal. What is the total force of friction and air resistance acting on the skier? (Use g = 9.8 m/s²)

    Hint: "Constant speed" means dynamic equilibrium. The net force is zero. But the forces are on an incline! You'll need to analyze the forces parallel to the slope. What component of gravity is pulling the skier down the slope?